By
Stephen Sommer, BSEE
Steve-
Last
Fall I had a 12 volt refrigeration system installed and recently
it seems to only work at night. Someone told me that the
compressor might be shutting down because it’s not getting
enough power and maybe the wire size is too small. Is this
possible and how can I find out without hiring a refrigeration
specialist?
First, check to make sure that you
have good cooling air (or water) flow through your condenser, lack
of which will certainly cause a shutdown, and is all the more
likely when it's hot outside. If that's OK, continue on.
I suspect that your problem is low
voltage at the input to the Adler Barbour control unit. It's easy
to suspect this because it is so common to have these wired with
long and small gauge wires. In your case, the fact that it runs OK
at night supports this. First, at night the air (or water) cooling
the condenser is cooler, so the compressor will see a lower
pressure head and draw less current (amps) which will reduce the
voltage loss in the wires. Second, if the batteries are
cooler at night, the voltage will be slightly higher. Third, if
you have a smart battery charger with temperature sensor, it will
charge at a slightly higher voltage, when it’s cooler.
The relevant place to check for low
voltage is at the input terminals of the unit, while it is
operating. You might have to measure it during nighttime
conditions and just assume it's a bit worse during the daytime.
Then, look up the minimum acceptable voltage in the specifications
that came with your unit. The number is probably 10.5
volts. If
your voltage is low, continue on.
Your problem with your fridge is the
oldest problem in 12-volt systems. The low voltage is
a problem in two ways. I'll explain. A refrigeration compressor
requires about 60 watts. Watts is equal to volts times amps.
In a similar size household fridge you could get the 60 watts with
1/2 amp and 120 volts. With 120 volts you could probably lose 5 or
10 volts to wiring losses and not notice it. In your boat
though, you need 5 amps at 12 volts, and you can tolerate 1/2 or
maybe one volt loss in wires. You are running 10 times as many
amps and have one tenth the tolerance for losses, which means you
need very heavy wires.
If you want to figure out the
required wire size analytically, here are a few rules of thumb:
Determine the loss budget for the wire in question. Remember
that all series losses add up, and both positive and negative
count. For example, if your minimum operating, under load,
battery voltage is 11.5 volts, and your fridge requires a minimum
of 10.5 volts, then you have 1.0 volt for all losses. If your
circuit breaker output, under load, is .5 volts less than the
battery voltage, then you only have .5 volts for loss.
A good rule of thumb to remember is: 10-gauge wire has .001 volt
of loss for every foot and every amp. For example, a 20 foot
10 gauge wire with 5 amps going through it will have 20feet x
5amps = .100 volt of loss. If it's a pair of wires, that's .2
volts. Another rule of thumb: For every three gauges of
increase, the loss is twice as great. So, 16-gauge wire has
.004 volts loss per foot, per amp. So if this 20-foot wire
pair was 16 gauge the loss would be .8 volts.
Your new wiring might not be the
only problem. To avoid other problems, the installation
instructions for the fridge probably says to connect directly to
the battery. Direct connections to the battery are a very bad
idea. Properly, there should be only one heavy wire on each
battery terminal. The single heavy wires should go directly
to the main disconnect switch and to the shunt for your battery
monitor and then to buss bars for distribution. The circuit
breaker for the fridge can be in the central distribution panel,
if you are confident that the wiring is heavy and short. The
circuit breaker should be as high a rating as is permissible by
the fridge installation instructions and the wiring used. The
reason for this is that a breaker, near it's rated current, will
be getting warm and allow a significant voltage drop. It goes
without saying that connections and crimps along the way should be
scrutinized.
For only $20 you can buy a digital
voltmeter that will measure voltages as little as .0001volt.
You can use it to see the loss of every foot of wire, crimp
connection, circuit breaker, switch and screw terminal. Just
remember, that all systems have to be operating to measure losses.
If the losses are too high, and the fridge won't run, just use an
incandescent 12-volt work light as a load of similar wattage,
while you are finding the problem.
Happy
Hunting!
Stephen
Sommer is a degreed electrical engineer with extensive experience
in electrical, mechanical, refrigeration and air conditioning
systems and holds a USCG Masters license. He consults in all areas
of yacht systems, which include all the equipment on board yachts
beyond a basic hull and motor or sails.